20t^2-20t+100=0

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Solution for 20t^2-20t+100=0 equation: 



20t^2-20t+100=0

a = 20; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·20·100
Δ = -7600
Delta is less than zero, so there is no solution for the equation

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